Home › CBSE Class 12 (Commerce) › Mathematics › Probability › If P(E ∩ F) = 0.12 and P(F) = 0.4, find P(E|F).
If P(E ∩ F) = 0.12 and P(F) = 0.4, find P(E|F).
A0.3
B0.48
C0.12
D0.5
Answer & Solution
Correct answer: A. 0.3
P(E|F) = 0.12 / 0.4 = 0.3 by dividing the joint probability by P(F).
Related questions
If P(A) = 0.6 and P(B) = 0.7, the smallest possible P(A and B) isA bag has 5 red, 3 green and 2 yellow marbles. P(red or yellow) isTwo dice are thrown. P(first die is 6 and sum is at least 11) isA card is drawn from ten cards numbered 1 to 10. P(2, 4, 6 or 8) isTwo fair dice are thrown. P(sum greater than 11) isTwo fair coins are tossed. P(exactly one head) isA fair die is rolled. P(a number less than 3) isIn P(A) + P(B), the sample points of A and B together are counted