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A box has 5 red and 3 blue balls. Two are drawn without replacement. P(both red)?
A5/14
B25/64
C5/16
D3/7
Answer & Solution
Correct answer: A. 5/14
P = (5/8) x (4/7) = 20/56 = 5/14, since only 4 red balls remain among 7 after the first draw.
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