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A wave is given by $y=A\sin(\omega t-kx)$. This wave travels
Aalong the $+x$-direction
Balong the $-x$-direction
Cas a standing wave
Dwith zero phase velocity
Answer & Solution
Correct answer: A. along the $+x$-direction
A travelling wave of the form $A\sin(\omega t-kx)$ or $A\sin(kx-\omega t)$ moves in the positive $x$-direction. In contrast, $A\sin(\omega t+kx)$ moves in the negative $x$-direction. Therefore the correct choice is A.
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