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For an open organ pipe of length $L$, the fundamental frequency corresponds to 
A$\lambda=L$
B$\lambda=4L$
C$\lambda=2L$
D$\lambda=\dfrac{L}{2}$
Answer & Solution
Correct answer: C. $\lambda=2L$
In an open organ pipe, both ends are displacement antinodes. For the first harmonic, the pipe contains half a wavelength, so $L=\lambda/2$. Hence $\lambda=2L$, which is option C.
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