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Pure CHCl3 and CH2Cl2 have vapour pressures 200 and 415 mm Hg at 298 K. For x(CH2Cl2) = 0.688, what is ptotal?
A285.5 mm Hg
B347.9 mm Hg
C415.0 mm Hg
D62.4 mm Hg
Answer & Solution
Correct answer: B. 347.9 mm Hg
ptotal = 200 + (415 - 200) x 0.688, which is 347.9 mm Hg.
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