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At 0.987 bar and 293 K (KH = 76.48 kbar), how many millimoles of N2 dissolve in 1 L of water?
A0.716
B7.16
C1.29
D55.5
Answer & Solution
Correct answer: A. 0.716
Moles equal 1.29 x 10^-5 times 55.5 mol of water, which is 7.16 x 10^-4 mol, or 0.716 mmol.
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