Order of boiling points of the given compound is: (1) pentan-1-ol (2) butan-1-ol (3) butan-2-ol (4) propan-1-ol
A$1 > 2 > 3 > 4$
B$1 > 3 > 2 > 4$
C$4 > 3 > 2 > 1$
D$4 > 2 > 3 > 1$
Answer & Solution
Correct answer: A. $1 > 2 > 3 > 4$
All these alcohols can form hydrogen bonds, so differences mainly come from molar mass and branching. Boiling point increases with chain length and decreases with branching. Therefore pentan-1-ol has the highest boiling point, followed by butan-1-ol, then butan-2-ol, and propan-1-ol is the lowest.
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