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Given the diazonium salt shown, which product is formed on treatment with $NaNO_2$, Cu and heat? ![](https://qallery.app/diagrams/v2_46c8b1655a73/img-001.jpeg)

AFluorobenzene ![](https://qallery.app/diagrams/v2_46c8b1655a73/img-002.jpeg)
BNitrobenzene ![](https://qallery.app/diagrams/v2_46c8b1655a73/img-003.jpeg)
C$m$-Nitrofluorobenzene ![](https://qallery.app/diagrams/v2_46c8b1655a73/img-004.jpeg)
D$p$-Nitrofluorobenzene ![](https://qallery.app/diagrams/v2_46c8b1655a73/img-005.jpeg)
Answer & Solution
Correct answer: B. Nitrobenzene ![](https://qallery.app/diagrams/v2_46c8b1655a73/img-003.jpeg)
The substrate is benzenediazonium tetrafluoroborate. On treatment with nitrite in presence of copper and heat, the diazonium group is replaced by $NO_2$, giving nitrobenzene. Fluorobenzene would arise from the Schiemann reaction on heating the diazonium tetrafluoroborate directly, but that is not the reaction asked here.
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