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What mass of silver is deposited when 9650 C passes through AgNO3 solution (Ag = 108)?
A1.08 g
B10.8 g
C108 g
D0.108 g
Answer & Solution
Correct answer: B. 10.8 g
9650 C is 0.1 F, which deposits 0.1 mol of silver, about 10.8 g.
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