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Given Lo for NaCl 126.4, HCl 425.9 and NaAc 91.0, what is Lo for HAc in S cm2 mol-1?
A643.3
B390.5
C426.8
D208.1
Answer & Solution
Correct answer: B. 390.5
Lo(HAc) = Lo(HCl) + Lo(NaAc) - Lo(NaCl) = 425.9 + 91.0 - 126.4 = 390.5.
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