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At 298 K, which relation links Eo of a two-electron cell to its equilibrium constant?
AEo = 0.059 log Kc
BEo = 2 x 0.059 log Kc
CEo = (0.059/2) log Kc
DEo = (2/0.059) log Kc
Answer & Solution
Correct answer: C. Eo = (0.059/2) log Kc
Setting E = 0 in the Nernst equation with n = 2 gives Eo = (0.059 V/2) log Kc.
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