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By convention, how is the emf of a galvanic cell written in terms of electrode potentials?

AEleft times Eright
BEleft minus Eright
CEright plus Eleft
DEright minus Eleft
Answer & Solution
Correct answer: D. Eright minus Eleft
With the anode on the left and cathode on the right, emf is the right half-cell potential minus the left one.
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