There is a horizontal film of soap solution. On it a thread is placed in the form of a loop. The film is pierced inside the loop and the thread becomes a circular loop of radius $R$. If the surface tension of the loop be $T$, then what will be the tension in the thread
A$\pi R^2 /T$
B$\pi R^2 T$
C$2\pi RT$
D$2RT$
Answer & Solution
Correct answer: D. $2RT$
After piercing the film inside the loop, soap film remains only outside the thread. A soap film has two surfaces, so the pull due to surface tension on the thread per unit length is $2T$ directed normally outward.
For a small element of the circular thread subtending angle $d\theta$, if the tension in the thread is $F$, the inward resultant due to thread tension is $F\,d\theta$.
The outward force due to surface tension on that element is $2T\,(R\,d\theta)$.
In equilibrium,
$$F\,d\theta = 2T R\,d\theta$$
So,
$$F = 2RT$$
Now compare with the options: this matches option $D$.
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