An element occurring in the $bcc$ structure has $12.08 \times 10^{23}$ unit cells. The total number of atoms of the element in these cells will be
A$12.08 \times 10^{23}$
B$36.18 \times 10^{23}$
C$6.04 \times 10^{23}$
D$24.16 \times 10^{23}$
Answer & Solution
Correct answer: D. $24.16 \times 10^{23}$
In a $bcc$ unit cell, the number of atoms per unit cell is $2$.
So total atoms are
$$2 \times 12.08 \times 10^{23}$$
$$24.16 \times 10^{23}$$
On checking the options, this matches option $D$.
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