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The Hardy-Weinberg equation p2 + 2pq + q2 = 1 is a binomial expansion of what?
A(p-q)2
B(p+q)2
C(p+q)3
D(pq)2
Answer & Solution
Correct answer: B. (p+q)2
Expanding (p+q)2 gives p2 + 2pq + q2, which equals 1 at equilibrium.
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