A concave mirror of focal length 15 cm forms an image of an object placed 10 cm in front of it. The image is
Areal, inverted and magnified
Breal, inverted and diminished
Cvirtual, erect and diminished
Dvirtual, erect and magnified
Answer & Solution
Correct answer: D. virtual, erect and magnified
$u=-10,\ f=-15$. $\frac1v=\frac1f-\frac1u=-\frac1{15}+\frac1{10}=\frac{1}{30}\Rightarrow v=+30$ cm (behind mirror, virtual). $m=-v/u=-30/(-10)=+3$ → erect, magnified. Object inside focus of a concave mirror always gives a virtual, erect, magnified image.
Related questions
Which property of a concave mirror makes it suitable for a dentist?A ray travelling parallel to the principal axis of a concave mirror is reflected:Where must an object sit for a concave mirror to form a virtual, magnified, erect image?What quantity is measured in lux and describes how many lumens fall on each square metre oFor yellow light with a wavelength of 6.00 x 10^-7 m, what frequency does c equals f timesOne light year is the distance light travels in one year. What is that distance in kilometA photographer measures 39.8 lux from a 2,000 lumen bulb held 2.00 m away, using illuminanPolarized sunglasses cut down glare from a lake. How do the lenses achieve this?