A concave mirror of focal length 15 cm forms an image of an object placed 10 cm in front of it. The image is
Areal, inverted and magnified
Breal, inverted and diminished
Cvirtual, erect and diminished
Dvirtual, erect and magnified
Answer & Solution
Correct answer: D. virtual, erect and magnified
$u=-10,\ f=-15$. $\frac1v=\frac1f-\frac1u=-\frac1{15}+\frac1{10}=\frac{1}{30}\Rightarrow v=+30$ cm (behind mirror, virtual). $m=-v/u=-30/(-10)=+3$ → erect, magnified. Object inside focus of a concave mirror always gives a virtual, erect, magnified image.
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