A tree breaks so that its top touches the ground at 30° to it, 6√3 m from the foot. What was the original tree height?
A6 m
B12 m
C24 m
D18 m
Answer & Solution
Correct answer: D. 18 m
The standing part is 6√3 times tan 30°, which is 6 m, the broken part is 6√3 divided by cos 30°, which is 12 m, and the total is 18 m.
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