The oxidation state of Cr in $[Cr(CO)_6]$ is (Z(Cr) = 24):
- +3
- +2
- +6
- 0
Show answer and solution
Correct answer: D. 0
CO is a neutral ligand (zero charge).
The complex is neutral, so Cr must have oxidation state **0**.
EAN = 24 − 0 + 12 = 36 (Kr config) — rule obeyed.