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US High School Mixture and Uniform Motion — practice questions

Explore 6 free Mixture and Uniform Motion questions in US High School Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Mixture and Uniform Motion questions and exercises with answers

Showing questions 1–6 of 6.

How do you find the total value of a pile of coins that are all the same type?Read the answer and worked solution →A pile holds 23 dimes, and each dime is worth 0.10 dollars. What is the pile worth?Read the answer and worked solution →A jar holds 20 coins, each a nickel worth 0.05 dollars or a dime worth 0.10 dollars, and they total 1.60 dollars. How many nickels are there?Read the answer and worked solution →What is a problem called when the speed of the moving object never changes?Read the answer and worked solution →A car holds a steady 60 miles per hour for 2.5 hours. How far does it travel?Read the answer and worked solution →Ana rides 5 miles per hour faster than Ben on the same route. Ben takes 3 hours and Ana takes 2 hours. How fast does Ben ride?Read the answer and worked solution →

Worked practice questions

How do you find the total value of a pile of coins that are all the same type?

  1. Multiply the number by the value
  2. Add the number to the value
  3. Divide the number by the value
  4. Subtract the value from the number
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Correct answer: A. Multiply the number by the value

1. Counting the coins tells you the number, but not yet what they are worth. 2. Each coin of one type carries the same value. 3. Number times value gives the total value of that pile. _Source: OpenStax Intermediate Algebra (CC BY 4.0), Ch 2 "Solving Linear Equations", section 2.4 Solve Mixture and Uniform Motion Applications_

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A pile holds 23 dimes, and each dime is worth 0.10 dollars. What is the pile worth?

  1. It is worth 23.10 dollars
  2. It is worth 0.23 dollars
  3. It is worth 2.30 dollars
  4. It is worth 230 dollars
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Correct answer: C. It is worth 2.30 dollars

1. Use number times value equals total value. 2. The number is 23 and the value of each dime is 0.10 dollars. 3. Multiplying gives 23 times 0.10, which is 2.30 dollars. 4. Answering 23.10 dollars adds the two numbers instead of multiplying them. _Source: OpenStax Intermediate Algebra (CC BY 4.0), Ch 2 "Solving Linear Equations", section 2.4 Solve Mixture and Uniform Motion Applications_

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A jar holds 20 coins, each a nickel worth 0.05 dollars or a dime worth 0.10 dollars, and they total 1.60 dollars. How many nickels are there?

  1. There are 12 nickels
  2. There are 8 nickels
  3. There are 4 nickels
  4. There are 16 nickels
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Correct answer: B. There are 8 nickels

1. Let n stand for the number of nickels. 2. Since there are 20 coins in all, the number of dimes is 20 minus n. 3. The nickels are worth 0.05n dollars and the dimes are worth 0.10 times 20 minus n. 4. Adding the two totals gives 0.05n plus 0.10 times 20 minus n equal to 1.60. 5. Expanding the bracket gives 0.05n plus 2 minus 0.10n equal to 1.60. 6. Combining like terms gives negative 0.05n plus 2 equal to 1.60, so negative 0.05n is negative 0.40. 7. Dividing gives n equal to 8, so there are 8 nickels. 8. Checking, 8 nickels give 0.40 dollars and 12 dimes give 1.20 dollars, totalling 1.60 dollars. 9. Answering 12 nickels reports the dime count instead of the nickel count. 10. Answering 16 nickels would make the total only 1.20 dollars, well short of 1.60. _Source: OpenStax Intermediate Algebra (CC BY 4.0), Ch 2 "Solving Linear Equations", section 2.4 Solve Mixture and Uniform Motion Applications_

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More Mathematics topics

Using the Normal DistributionLinear InequalitiesSolving Linear EquationsAbsolute Value Equations and InequalitiesCompound InequalitiesProblem Solving with EquationsSolving a Formula for a VariableThe Standard Normal Distribution