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UP Police SI Averages — practice questions — page 2

Explore 38 free Averages questions in UP Police SI Quantitative Aptitude. Open each question or exercise to read its content, reference answers and available explanation.

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Averages questions and exercises with answers

Showing questions 31–38 of 38.

The three measures of central tendency are:Read the answer and worked solution →The average of the first 10 natural numbers is:Read the answer and worked solution →The average of 10 numbers is 45. A new number, 100, is added to the set. The new average is:Read the answer and worked solution →The class mark of the class interval 10-25 is:Read the answer and worked solution →The average of 6 numbers is 8. If the number 12 is removed, the average of the remaining 5 is:Read the answer and worked solution →In a branch, 30 clerks average 60 marks and 20 officers average 70. The average of all 50 staff is:Read the answer and worked solution →The average of 15 numbers is 12. The first 8 average 11 and the last 8 average 14. The 8th number is:Read the answer and worked solution →A batsman's average over 16 innings is 36. To raise the average to 38 in the 17th innings, he must score:Read the answer and worked solution →

Worked practice questions

The three measures of central tendency are:

  1. Mean, range and mode
  2. Median, range and total
  3. Mean, median and mode
  4. Mode, range and frequency
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Correct answer: C. Mean, median and mode

1. A measure of central tendency is a single number standing in for a whole data set. 2. The three studied are mean, median and mode. 3. The mean is the arithmetic average, the median the middle value, the mode the most frequent value. 4. Range is a measure of spread, not of centre, so any option containing it is wrong. _Source: syllabus Maths, Ch 13 'Statistics', S13.1 Introduction_

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The average of the first 10 natural numbers is:

  1. 5.5
  2. 5
  3. 6
  4. 6.5
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Correct answer: A. 5.5

1. The first 10 natural numbers are 1 through 10. 2. Their sum is 10 x 11 / 2 = 55. 3. The average is the sum divided by the count, so 55 / 10. 4. That gives 5.5. 5. Answering 5 would be taking the middle of 1 to 10 carelessly; with an even count the mean falls between 5 and 6. _Source: syllabus Maths, Ch 13 'Statistics', S13.2 Mean of Grouped Data_

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The average of 10 numbers is 45. A new number, 100, is added to the set. The new average is:

  1. 45
  2. 50
  3. 55
  4. 72.5
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Correct answer: B. 50

1. Recover the total first: average x count = 45 x 10 = 450. 2. Adding the new number makes the total 450 + 100 = 550. 3. The count is now 11. 4. So the new average is 550 / 11 = 50. 5. 72.5 comes from averaging 45 and 100 directly, which ignores that one number cannot outweigh ten. _Source: syllabus Maths, Ch 13 'Statistics', S13.2 Mean of Grouped Data_

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