Find the HCF of 6xy²z, 8x²y³z² and 12x³y³z³.
- 2xy²z
- 2xyz
- 4xy²z
- 3xy²z
Show answer and solution
Correct answer: A. 2xy²z
1. HCF of coefficients 6, 8, 12 is 2.
2. Lowest powers: x¹, y², z¹ (the minimum exponent of each variable across the terms).
3. HCF = 2xy²z.
_Source: RRB Group D CEN-02/2018 PYQ, Q.16._