alleryStart learning →Triangle ABC is right-angled at B with AB = 5 and BC = 12. Find sin A.
- 5/13
- 12/5
- 12/13
- 5/12
Show answer and solution
Correct answer: C. 12/13
AC = 13 and the side opposite A is BC = 12, so sin A = 12/13.
SSC CGL Trigonometry — practice questions — page 2
Explore 54 free Trigonometry questions in SSC CGL Quantitative Aptitude. Open each question or exercise to read its content, reference answers and available explanation.
Practise Trigonometry with Quill →Trigonometry questions and exercises with answers
Showing questions 31–54 of 54.
Triangle ABC is right-angled at B with AB = 5 and BC = 12. Find sin A.Read the answer and worked solution →A 30 m tower casts a shadow when the sun's elevation is 30°. Find the shadow length.Read the answer and worked solution →From a point 30 m from the foot of a tower, the top has elevation 30°. Find the height.Read the answer and worked solution →In triangle ABC, sin((A + B)/2) equalsRead the answer and worked solution →Express 120° in radians.Read the answer and worked solution →Convert 5π/6 radians to degrees.Read the answer and worked solution →In a triangle, a = 10, A = 30° and B = 45°. Find side b.Read the answer and worked solution →A triangle has side 6 opposite an angle of 30°. What is its circumradius?Read the answer and worked solution →Two sides of a triangle are 5 and 7 with a 60° angle between them. Find the third side.Read the answer and worked solution →A triangle has sides 3, 5 and 7. Find the angle opposite the longest side.Read the answer and worked solution →Sides 10 and 12 enclose an angle of 45°. What is the triangle's area?Read the answer and worked solution →For any angle θ, sin(−θ) is equal toRead the answer and worked solution →What does tan 135° equal?Read the answer and worked solution →Both sin θ and cos θ are negative when θ lies inRead the answer and worked solution →If cos θ > 0 and tan θ < 0, the angle θ lies inRead the answer and worked solution →What is the smallest positive period of tan θ in degrees?Read the answer and worked solution →What is the minimum value of sec²θ + cosec²θ?Read the answer and worked solution →Using cos²θ = (1 + cos 2θ)/2, find cos²15°.Read the answer and worked solution →In a right triangle, cot θ is the ratio ofRead the answer and worked solution →Evaluate sin 90° + cos 0° + tan 45°.Read the answer and worked solution →If sin(A + B) = 1 and cos(A − B) = √3/2 for acute angles, find A and B.Read the answer and worked solution →If tan(A + B) = √3 and tan(A − B) = 1/√3, find A.Read the answer and worked solution →A pole is broken so its top touches the ground 6 m from the base at 30° to the ground. Find the original height.Read the answer and worked solution →From the top of a 90 m tower the angle of depression of a boat is 60°. How far is the boat from the tower's foot?Read the answer and worked solution →
Worked practice questions
A 30 m tower casts a shadow when the sun's elevation is 30°. Find the shadow length.
- 30√3 m
- 30 m
- 15√3 m
- 10√3 m
Show answer and solution
Correct answer: A. 30√3 m
Shadow = 30 / tan 30° = 30√3 m.
From a point 30 m from the foot of a tower, the top has elevation 30°. Find the height.
- 30 m
- 10√3 m
- 15 m
- 30√3 m
Show answer and solution
Correct answer: B. 10√3 m
Height = 30 tan 30° = 30/√3 = 10√3 m.
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