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SNAP Pipes and Cisterns — practice questions — page 2

Explore 34 free Pipes and Cisterns questions in SNAP Quantitative Aptitude. Open each question or exercise to read its content, reference answers and available explanation.

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Pipes and Cisterns questions and exercises with answers

Showing questions 31–34 of 34.

A train 200 m long crosses a 100 m platform at 36 km per hour. It takes:Read the answer and worked solution →A man travels equal distances at 40 km per hour and at 60 km per hour. His average speed is:Read the answer and worked solution →A man covers a distance in 6 hours at 40 km per hour. To cover it in 4 hours he must travel at:Read the answer and worked solution →A car uses 4 litres of petrol for 60 km. Its mileage in km per litre is:Read the answer and worked solution →

Worked practice questions

A train 200 m long crosses a 100 m platform at 36 km per hour. It takes:

  1. 20 seconds
  2. 25 seconds
  3. 30 seconds
  4. 36 seconds
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Correct answer: C. 30 seconds

1. To cross a platform the train must cover its own length plus the platform's length. 2. That total is 200 + 100 = 300 m. 3. Convert the speed: 36 x 5 / 18 = 10 metres per second. 4. The time is 300 / 10 = 30 seconds. 5. Using only the train's length would give 20 seconds, which is the trap distractor here. _Source: syllabus Maths, Ch 11 'Direct and Inverse Proportions', S11.3 Inverse Proportion_

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A man travels equal distances at 40 km per hour and at 60 km per hour. His average speed is:

  1. 46 km per hour
  2. 48 km per hour
  3. 50 km per hour
  4. 52 km per hour
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Correct answer: B. 48 km per hour

1. Average speed is total distance divided by total time, never the mean of the two speeds. 2. Take each leg as 120 km, a convenient common multiple. 3. The first leg takes 120 / 40 = 3 hours and the second 120 / 60 = 2 hours. 4. So 240 km takes 5 hours. 5. The average speed is 240 / 5 = 48 km per hour. Answering 50 is the mean-of-speeds trap, and it is always too high. _Source: syllabus Maths, Ch 11 'Direct and Inverse Proportions', S11.3 Inverse Proportion_

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A man covers a distance in 6 hours at 40 km per hour. To cover it in 4 hours he must travel at:

  1. 50 km per hour
  2. 55 km per hour
  3. 65 km per hour
  4. 60 km per hour
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Correct answer: D. 60 km per hour

1. First find the distance: 40 x 6 = 240 km. 2. The distance does not change, so speed and time are in inverse proportion. 3. The required speed is 240 / 4. 4. That is 60 km per hour. 5. Checking the ratio, the time fell to two thirds, so the speed must rise to three halves: 40 x 3 / 2 = 60. _Source: syllabus Maths, Ch 11 'Direct and Inverse Proportions', S11.3 Inverse Proportion_

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More Quantitative Aptitude topics

Quantitative AptitudeAlgebraNumber SystemTime Speed and DistanceTime and WorkModern MathematicsRatio and ProportionSpeed Distance