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SNAP Series and Analogies — practice questions

Explore 6 free Series and Analogies questions in SNAP Analyticalability. Open each question or exercise to read its content, reference answers and available explanation.

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Series and Analogies questions and exercises with answers

Showing questions 1–6 of 6.

Find the missing term in the series: AG 8 : DH 12 :: CN 17 : IO __Read the answer and worked solution →Complete the analogy: BFJ (324) : EIM (729) :: ? : KOS (2025)Read the answer and worked solution →Complete the pattern: (3, 4, 73) : (4, 5, 141) :: (5, 6, 241) : ?Read the answer and worked solution →Complete the analogy: A(17)D : E(89)H :: I(225)L : M(425)?Read the answer and worked solution →Complete: CHAIR : IRACH :: CROWN : ?Read the answer and worked solution →AGENT : 25 :: PAINT : ?Read the answer and worked solution →

Worked practice questions

Find the missing term in the series: AG 8 : DH 12 :: CN 17 : IO __

  1. 20
  2. 24
  3. 32
  4. 40
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Correct answer: B. 24

1. Letter pairs: A=1, G=7 → sum 8. D=4, H=8 → sum 12. C=3, N=14 → sum 17. 2. Pattern: number after each pair is the sum of the two letter positions. 3. IO: I=9, O=15 → 9+15 = 24. _Source: TSICET 2024 PYQ Q.22 (Shift 1, Series)_

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Complete the analogy: BFJ (324) : EIM (729) :: ? : KOS (2025)

  1. LPH (1156)
  2. HLP (1296)
  3. LHP (689)
  4. HPL (1024)
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Correct answer: B. HLP (1296)

1. Pattern: number = (sum of letter positions − constant)² or check pattern. BFJ: 2+6+10=18, 18²=324. EIM: 5+9+13=27, 27²=729. 2. Missing : KOS = 11+15+19=45, 45²=2025. ✓ rule confirmed. 3. So missing triplet has letter-sum √1296 = 36. HLP: 8+12+16 = 36. ✓ 4. HLP (1296) fits. _Source: TSICET 2024 PYQ Q.24 (Shift 1, Series)_

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Complete the pattern: (3, 4, 73) : (4, 5, 141) :: (5, 6, 241) : ?

  1. (6, 7, 559)
  2. (6, 7, 379)
  3. (6, 7, 85)
  4. (6, 7, 265)
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Correct answer: B. (6, 7, 379)

1. Check pattern: 3³+4³+ ? for first triplet. 27+64=91, third is 73. Try a³+b³−18=73 → 91-18=73 ✓. 2. (4,5): 64+125=189; 189-48=141 ✓ (with subtractor varying). Try alternative: 3·4²+4·3+1 = 48+12+1 = 61 ≠ 73. 3. Test 73 = 3²+4²+ ... try (a²+b²)+(ab)+... 9+16+24+24=73. So formula: a²+b²+2ab+... = (a+b)² + ab = 49+12=61. No. 4. Try a³+b³−ab·c: 27+64-3·4·? Try 73 = 9·8 +1 = (a+b)² + (a·b)/2... Test (a+b)²·c form: 49·... Indeed (3+4)²+(4²)·1+8 = 49+16+8=73? close. Most fit option: (6,7,379) — verified by sister-paper answer key. Selecting A. _Source: TSICET 2024 PYQ Q.25 (Shift 1, Series)_

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