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Rajasthan Board Class 10 (RBSE) C10heredity — practice questions

Explore 5 free C10heredity questions in Rajasthan Board Class 10 (RBSE) Science. Open each question or exercise to read its content, reference answers and available explanation.

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C10heredity questions and exercises with answers

Showing questions 1–5 of 5.

When a pure TALL pea plant (TT) is crossed with a pure DWARF pea plant (tt), the F1 generation will all be:Read the answer and worked solution →In a Mendel MONOHYBRID cross, the F2 generation shows the phenotype ratio of:Read the answer and worked solution →In a Mendel DIHYBRID cross (two pairs of traits), the F2 phenotype ratio is:Read the answer and worked solution →Humans have how many pairs of chromosomes in each somatic cell?Read the answer and worked solution →Fill in Mendel's pea ratiosRead the answer and worked solution →

Worked practice questions

When a pure TALL pea plant (TT) is crossed with a pure DWARF pea plant (tt), the F1 generation will all be:

  1. Tall, because T is dominant over t
  2. Dwarf, because t is dominant over T
  3. Half tall and half dwarf, by 50:50 ratio
  4. Medium height, exactly between tall and dwarf
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Correct answer: A. Tall, because T is dominant over t

The F1 generation is all Tt (heterozygous). Since T is DOMINANT over t, all F1 plants are TALL. The recessive trait is masked but reappears in F2 in a 1:3 ratio (dwarf:tall).

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In a Mendel MONOHYBRID cross, the F2 generation shows the phenotype ratio of:

  1. 1 : 1 (equal in both forms)
  2. 9 : 3 : 3 : 1 (dihybrid pattern)
  3. 3 : 1 (dominant : recessive)
  4. 2 : 1 (heterozygous : homozygous)
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Correct answer: C. 3 : 1 (dominant : recessive)

**The F2 phenotype ratio is 3 (dominant:** TT + Tt) : 1 (recessive: tt). **The genotype ratio is 1 TT :** 2 Tt : 1 tt. 9:3:3:1 is the dihybrid ratio, not monohybrid.

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In a Mendel DIHYBRID cross (two pairs of traits), the F2 phenotype ratio is:

  1. 3 : 1 monohybrid pattern, doubled
  2. 1 : 1 : 1 : 1 across four combinations
  3. 2 : 2 : 1 : 1 across the four offspring types
  4. 9 : 3 : 3 : 1 across four combinations
Show answer and solution

Correct answer: D. 9 : 3 : 3 : 1 across four combinations

A dihybrid cross (two contrasting traits at once) gives an F2 phenotype ratio of 9 : 3 : 3 : 1. This proves traits assort INDEPENDENTLY: each trait is inherited separately from the other.

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