If $y = x \sin x$, then $y_2 = \dfrac{d^2y}{dx^2}$ equals:
- $-x\sin x$
- $x\cos x$
- $2\cos x - x \sin x$
- $\cos x + \sin x$
Show answer and solution
Correct answer: C. $2\cos x - x \sin x$
$y' = \sin x + x\cos x$.
$y'' = \cos x + \cos x + x(-\sin x) = 2\cos x - x\sin x$.