alleryStart learning →$\displaystyle\int_0^\infty x^3 e^{-x}\, dx = ?$
- $3!$
- $3$
- $e^{-3}$
- $\infty$
Show answer and solution
Correct answer: A. $3!$
**Gamma:** $\Gamma(n+1) = \int_0^\infty x^n e^{-x}\, dx = n!$.
Here $n = 3$: result $= 3! = 6$.
PUCET (Punjab) Gamma — practice questions
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