alleryStart learning →$\displaystyle\int_0^\pi \sin x\, dx = ?$
- $0$
- $1$
- $2$
- $\pi$
Show answer and solution
Correct answer: C. $2$
$[-\cos x]_0^\pi = -\cos\pi + \cos 0 = 1 + 1 = 2$.
PUCET (Punjab) Basic — practice questions
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