If $\vec a = 4\hat i + 3\hat k$ and $\vec b = -2\hat i + \hat j + 5\hat k$, then $2\vec a + 5\vec b$ equals:
- $-2\hat i + 5\hat j + 31\hat k$
- $18\hat i + 5\hat j + 31\hat k$
- $2\hat i + 5\hat j - 31\hat k$
- $-2\hat i + \hat j + 8\hat k$
Show answer and solution
Correct answer: A. $-2\hat i + 5\hat j + 31\hat k$
$2\vec a = 8\hat i + 6\hat k$
$5\vec b = -10\hat i + 5\hat j + 25\hat k$.
**Sum:** $-2\hat i + 5\hat j + 31\hat k$.