The sum of three consecutive integers starting at n is
- 3n + 3
- 3n + 2
- n + 3
- 3n
Show answer and solution
Correct answer: A. 3n + 3
n + (n + 1) + (n + 2) = 3n + 3.
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Correct answer: A. 3n + 3
Correct answer: B. 13
Correct answer: C. 41
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