Start learning →

NMAT Pipes and Cisterns — practice questions — page 2

Explore 34 free Pipes and Cisterns questions in NMAT Quantitative Aptitude. Open each question or exercise to read its content, reference answers and available explanation.

Practise Pipes and Cisterns with Quill →

Pipes and Cisterns questions and exercises with answers

Showing questions 31–34 of 34.

A train 200 m long crosses a 100 m platform at 36 km per hour. It takes:Read the answer and worked solution →A man travels equal distances at 40 km per hour and at 60 km per hour. His average speed is:Read the answer and worked solution →A man covers a distance in 6 hours at 40 km per hour. To cover it in 4 hours he must travel at:Read the answer and worked solution →A car uses 4 litres of petrol for 60 km. Its mileage in km per litre is:Read the answer and worked solution →

Worked practice questions

A train 200 m long crosses a 100 m platform at 36 km per hour. It takes:

  1. 20 seconds
  2. 25 seconds
  3. 30 seconds
  4. 36 seconds
Show answer and solution

Correct answer: C. 30 seconds

1. To cross a platform the train must cover its own length plus the platform's length. 2. That total is 200 + 100 = 300 m. 3. Convert the speed: 36 x 5 / 18 = 10 metres per second. 4. The time is 300 / 10 = 30 seconds. 5. Using only the train's length would give 20 seconds, which is the trap distractor here. _Source: syllabus Maths, Ch 11 'Direct and Inverse Proportions', S11.3 Inverse Proportion_

Open this question →

A man travels equal distances at 40 km per hour and at 60 km per hour. His average speed is:

  1. 46 km per hour
  2. 48 km per hour
  3. 50 km per hour
  4. 52 km per hour
Show answer and solution

Correct answer: B. 48 km per hour

1. Average speed is total distance divided by total time, never the mean of the two speeds. 2. Take each leg as 120 km, a convenient common multiple. 3. The first leg takes 120 / 40 = 3 hours and the second 120 / 60 = 2 hours. 4. So 240 km takes 5 hours. 5. The average speed is 240 / 5 = 48 km per hour. Answering 50 is the mean-of-speeds trap, and it is always too high. _Source: syllabus Maths, Ch 11 'Direct and Inverse Proportions', S11.3 Inverse Proportion_

Open this question →

A man covers a distance in 6 hours at 40 km per hour. To cover it in 4 hours he must travel at:

  1. 50 km per hour
  2. 55 km per hour
  3. 65 km per hour
  4. 60 km per hour
Show answer and solution

Correct answer: D. 60 km per hour

1. First find the distance: 40 x 6 = 240 km. 2. The distance does not change, so speed and time are in inverse proportion. 3. The required speed is 240 / 4. 4. That is 60 km per hour. 5. Checking the ratio, the time fell to two thirds, so the speed must rise to three halves: 40 x 3 / 2 = 60. _Source: syllabus Maths, Ch 11 'Direct and Inverse Proportions', S11.3 Inverse Proportion_

Open this question →

How to practise

  1. Choose a Pipes and Cisterns question and try to work out your answer.
  2. Open the question to check the correct answer and read its worked solution.
  3. Continue in the app for bite-sized lessons, explanations and review with Quill. You can start without creating an account.

More Quantitative Aptitude topics

Quantitative AptitudeNumber SystemAlgebraRatio and ProportionTime, Speed and DistanceTime and WorkPercentagesSimple Interest