If $f(x)$ is an **odd** function, then $\int_{-a}^{a} f(x)\,dx$ equals:
- $2\int_0^a f(x)\,dx$
- $0$
- $\int_0^a f(x)\,dx$
- $-2\int_0^a f(x)\,dx$
Show answer and solution
Correct answer: B. $0$
For odd $f$: $f(-x) = -f(x)$, so contributions from $[-a, 0]$ and $[0, a]$ cancel exactly.
**Hence $\int_{-a}^{a} f = 0$.**