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MP Board Class 12 (MPBSE) Physics — practice by topic

Browse 259 questions across 27 Physics topics. Choose what you want to revise, then open a question to check its answer and worked solution.

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The critical angle for total internal reflection at a glass-air interface is $42^\circ$. The refractive index of the glass is approximately:Read the answer and worked solution →An object is placed $30\,\text{cm}$ in front of a concave mirror of focal length $20\,\text{cm}$. The image distance from the mirror is:Read the answer and worked solution →Two plane mirrors are inclined at an angle of $60^\circ$. The number of images of a point object placed between them is:Read the answer and worked solution →A convex mirror always forms an image of a real object that is:Read the answer and worked solution →

Worked practice questions

The critical angle for total internal reflection at a glass-air interface is $42^\circ$. The refractive index of the glass is approximately:

  1. $1.33$
  2. $1.41$
  3. $1.49$
  4. $2.42$
Show answer and solution

Correct answer: C. $1.49$

For total internal reflection at a denser-to-rarer interface, $\mu = \dfrac{1}{\sin C}$. With $C = 42^\circ$, $\sin 42^\circ \approx 0.669$, so $\mu = 1/0.669 \approx 1.49$, which matches typical crown glass. **Option A is water and option D is diamond.**

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An object is placed $30\,\text{cm}$ in front of a concave mirror of focal length $20\,\text{cm}$. The image distance from the mirror is:

  1. $+12\,\text{cm}$
  2. $-60\,\text{cm}$
  3. $+60\,\text{cm}$
  4. $-12\,\text{cm}$
Show answer and solution

Correct answer: B. $-60\,\text{cm}$

Using the standard sign convention, $u = -30\,\text{cm}$ and $f = -20\,\text{cm}$ for a concave mirror. The mirror formula $\dfrac{1}{v} + \dfrac{1}{u} = \dfrac{1}{f}$ gives $\dfrac{1}{v} = \dfrac{1}{-20} - \dfrac{1}{-30} = -\dfrac{1}{60}$, so $v = -60\,\text{cm}$. The negative sign indicates the image is real and on the same side as the object, $60\,\text{cm}$ in front of the mirror.

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Two plane mirrors are inclined at an angle of $60^\circ$. The number of images of a point object placed between them is:

  1. $3$
  2. $4$
  3. $5$
  4. $6$
Show answer and solution

Correct answer: C. $5$

When $360^\circ/\theta$ is an integer, the number of images is $n = \dfrac{360^\circ}{\theta} - 1$. Here $360^\circ/60^\circ = 6$, an integer, so $n = 6 - 1 = 5$.

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