alleryStart learning →Find the pH of a 0.01 M HCl solution.
- 1
- 2
- 12
- 0.01
Show answer and solution
Correct answer: B. 2
HCl is fully ionised, so [H3O+] = 10^-2 M and pH = 2.
MHT-CET Ionic Equilibria — practice questions — page 2
Explore 77 free Ionic Equilibria questions in MHT-CET Chemistry. Open each question or exercise to read its content, reference answers and available explanation.
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Showing questions 31–60 of 77.
Find the pH of a 0.01 M HCl solution.Read the answer and worked solution →The pH of a 0.001 M NaOH solution at 298 K isRead the answer and worked solution →The pH of 0.005 M H2SO4, assuming complete ionization of both protons, isRead the answer and worked solution →A solution has [H3O+] of 1 x 10^-9 M. Its [OH-] and nature areRead the answer and worked solution →In an acidic aqueous solution at 298 K the pH isRead the answer and worked solution →The pH of gastric juice is aboutRead the answer and worked solution →The pH of human blood is maintained within the rangeRead the answer and worked solution →The enzyme trypsin acts best in which pH condition?Read the answer and worked solution →Mixing 50 mL of 0.1 M HCl with 50 mL of 0.1 M NaOH gives a solution of pHRead the answer and worked solution →What is the reaction of salt ions with water called?Read the answer and worked solution →Which of these salts is derived from a strong acid and a strong base?Read the answer and worked solution →Which salt is made from both a weak acid and a weak base?Read the answer and worked solution →An aqueous solution of NaCl isRead the answer and worked solution →Why does a CuSO4 solution look turbid on standing in water?Read the answer and worked solution →To obtain a clear solution of CuSO4, which should be added?Read the answer and worked solution →Aqueous CH3COONa is basic becauseRead the answer and worked solution →Aqueous HCOOK isRead the answer and worked solution →The salt of a weak acid and weak base with Ka = Kb gives a solution that isRead the answer and worked solution →Aqueous NH4F (HF Ka 7.2 x 10^-4; NH4OH Kb 1.8 x 10^-5) isRead the answer and worked solution →Aqueous CH3COONH4 (Ka = Kb = 1.8 x 10^-5) isRead the answer and worked solution →NH4CN solution turns red litmus blue becauseRead the answer and worked solution →A buffer solution is one that resists change inRead the answer and worked solution →An acidic buffer contains a weak acid andRead the answer and worked solution →Which pair forms a basic buffer?Read the answer and worked solution →The Henderson-Hasselbalch equation for an acidic buffer isRead the answer and worked solution →A buffer has equal concentrations of weak acid and its salt. Its pH equalsRead the answer and worked solution →Diluting a buffer solution does not change its pH becauseRead the answer and worked solution →In an acetate buffer, added H+ is consumed mainly byRead the answer and worked solution →What is the pH of a buffer of 0.05 M NaF and 0.015 M HF (Ka = 7.2 x 10^-4)?Read the answer and worked solution →Which buffer pair keeps blood pH at 7.36 to 7.42?Read the answer and worked solution →
Worked practice questions
The pH of a 0.001 M NaOH solution at 298 K is
- 3
- 10
- 12
- 11
Show answer and solution
Correct answer: D. 11
[OH-] = 10^-3 M so pOH = 3 and pH = 14 - 3 = 11.
The pH of 0.005 M H2SO4, assuming complete ionization of both protons, is
- 2
- 2.3
- 3
- 1
Show answer and solution
Correct answer: A. 2
Each mole of H2SO4 gives 2 moles of H+, so [H+] = 0.01 M and pH = 2.
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