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Maharashtra SSC (Class 10) Coordinate Geometry — practice questions — page 2

Explore 34 free Coordinate Geometry questions in Maharashtra SSC (Class 10) Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Coordinate Geometry questions and exercises with answers

Showing questions 31–34 of 34.

If a point is reflected in the x-axis, the new co-ordinates of (a, b) becomeRead the answer and worked solution →The distance of point (5, 0) from the origin isRead the answer and worked solution →The mid-point of the segment joining (-2, -3) and (4, 5) isRead the answer and worked solution →Sort points into their quadrantsRead the answer and worked solution →

Worked practice questions

If a point is reflected in the x-axis, the new co-ordinates of (a, b) become

  1. (-a, b)
  2. (a, -b)
  3. (-a, -b)
  4. (b, a)
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Correct answer: B. (a, -b)

1. Reflection in x-axis flips the sign of the y-coordinate. 2. x stays the same. 3. So (a, b) becomes (a, -b). 4. Hence option A is correct. _Source: Selina Concise Mathematics Class 9, Ch 26 Co-ordinate Geometry (Mistral OCR'd PDF), section on reflection_

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The distance of point (5, 0) from the origin is

  1. 10 units
  2. 5 units
  3. 0 units
  4. 25 units
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Correct answer: B. 5 units

1. Use d = sqrt(x^2 + y^2). 2. = sqrt(5^2 + 0^2) = sqrt(25). 3. = 5 units. 4. So the distance is 5 units. _Source: Selina Concise Mathematics Class 9, Ch 26 Co-ordinate Geometry (Mistral OCR'd PDF), section on distance from origin_

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The mid-point of the segment joining (-2, -3) and (4, 5) is

  1. (-1, -1)
  2. (3, 4)
  3. (2, 2)
  4. (1, 1)
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Correct answer: D. (1, 1)

1. Mid-point = ((x1 + x2)/2, (y1 + y2)/2). 2. = ((-2 + 4)/2, (-3 + 5)/2). 3. = (2/2, 2/2) = (1, 1). 4. So mid-point is (1, 1). _Source: Selina Concise Mathematics Class 9, Ch 26 Co-ordinate Geometry (Mistral OCR'd PDF), section on mid-point formula_

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