The number $\sqrt{2}$ is
- an irrational number
- a natural number
- a rational number
- an integer
Show answer and solution
Correct answer: A. an irrational number
1. A rational number can be written as p/q with integers p, q (q≠0).
2. $\sqrt{2}$ cannot be written this way; it is an **irrational number** (proved by contradiction).
3. Its decimal expansion is non-terminating and non-repeating.
_Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch8 'Real Numbers', §8.4_