The SI unit Henry (H) is equivalent to:
- $\text{Wb}\cdot\text{A}$
- $\text{V}\cdot\text{s}\cdot\text{A}^{-1}$
- $\text{T}\cdot\text{m}^2$
- $\text{V}\cdot\text{A}^{-1}$
Show answer and solution
Correct answer: B. $\text{V}\cdot\text{s}\cdot\text{A}^{-1}$
From $\varepsilon = -L \dfrac{dI}{dt}$, $L$ has units of $\text{V}/(\text{A/s}) = \text{V}\cdot\text{s}\cdot\text{A}^{-1}$.
This is the same as $\text{Wb}/\text{A}$ since $1\,\text{Wb} = 1\,\text{V}\cdot\text{s}$.