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Karnataka PUC II Moving Charges and Magnetism — practice questions — page 5

Explore 193 free Moving Charges and Magnetism questions in Karnataka PUC II Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Moving Charges and Magnetism questions and exercises with answers

Showing questions 121–150 of 193.

The magnetic field inside a toroidal solenoid with N total turns, mean radius r, carrying current I isRead the answer and worked solution →The period of revolution of a charged particle moving in a uniform magnetic field perpendicular to its velocity isRead the answer and worked solution →An electron enters a uniform magnetic field B at angle θ to B with speed v. The pitch of its helical path isRead the answer and worked solution →A cyclotron of dee radius R accelerates ions of charge q, mass m in a magnetic field B. The maximum kinetic energy isRead the answer and worked solution →A circular loop of radius R carries current I. The magnetic field at a point on its axis at distance x from the centre isRead the answer and worked solution →At the very end of a long solenoid, the magnetic field along the axis isRead the answer and worked solution →A magnetic dipole with moment m makes angle θ with a uniform field B. The torque on the dipole has magnitudeRead the answer and worked solution →An electron moves east in a magnetic field directed north. The magnetic force on the electron pointsRead the answer and worked solution →A cyclotron operates at frequency f in a magnetic field B. The charge-to-mass ratio of the accelerated ion isRead the answer and worked solution →Cyclotrons are not used to accelerate electrons becauseRead the answer and worked solution →A charge q moves with velocity v through a region with electric field E and magnetic field B. The net electromagnetic force on it isRead the answer and worked solution →Reading the Lorentz forceRead the answer and worked solution →Force on a current wireRead the answer and worked solution →The current carrying conductorRead the answer and worked solution →The cyclotron machineRead the answer and worked solution →Formula to what it describesRead the answer and worked solution →Using Biot-SavartRead the answer and worked solution →Odd one out: magnetismRead the answer and worked solution →Which is largerRead the answer and worked solution →Odd one out: what a current doesRead the answer and worked solution →Zero work, changing directionRead the answer and worked solution →Moving charges, mixed checkRead the answer and worked solution →A circular coil of N turns and radius R carries current I. Its magnetic dipole moment isRead the answer and worked solution →The Lorentz forceRead the answer and worked solution →A long solenoid has 1000 turns per metre and carries 2 A. The magnetic field strength inside isRead the answer and worked solution →A square coil of side 0.1 m, with 50 turns, carries 1 A in a 0.2 T field. The maximum torque on the coil isRead the answer and worked solution →Charge in a uniform fieldRead the answer and worked solution →Count and computeRead the answer and worked solution →Field of a circular coilRead the answer and worked solution →Two long parallel wires 0.1 m apart carry 5 A and 10 A in the same direction. The force per unit length on each wire isRead the answer and worked solution →

Worked practice questions

The magnetic field inside a toroidal solenoid with N total turns, mean radius r, carrying current I is

  1. μ₀NI
  2. μ₀NI/(2πr)
  3. 2πr·μ₀NI
  4. μ₀NI/r
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Correct answer: B. μ₀NI/(2πr)

1. Use Ampere's law along a circular path of radius r inside the toroid. 2. By symmetry, B is tangential: ∮B·dl = B·(2πr). 3. The enclosed current is NI. 4. Therefore B = μ₀NI/(2πr). _Source: syllabus Physics Ch 4 "Moving Charges and Magnetism", §4.8.2_

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The period of revolution of a charged particle moving in a uniform magnetic field perpendicular to its velocity is

  1. 2πqB/m
  2. qB/(2πm)
  3. m/(2πqB)
  4. 2πm/(qB)
Show answer and solution

Correct answer: D. 2πm/(qB)

1. Magnetic force provides centripetal force: qvB = mv²/r. 2. Orbital speed v = qBr/m, so angular velocity ω = v/r = qB/m. 3. Period T = 2π/ω = 2πm/(qB). 4. Notice T is independent of v and r, so the cyclotron frequency stays constant as the particle gains energy. _Source: syllabus Physics Ch 4 "Moving Charges and Magnetism", §4.3_

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An electron enters a uniform magnetic field B at angle θ to B with speed v. The pitch of its helical path is

  1. 2πm v sin θ / (eB)
  2. 2πm v cos θ / (eB)
  3. 2πm v / (eB)
  4. m v cos θ / (eB)
Show answer and solution

Correct answer: B. 2πm v cos θ / (eB)

1. Decompose velocity: parallel v∥ = v cos θ and perpendicular v⊥ = v sin θ. 2. The perpendicular component drives circular motion with period T = 2πm/(eB). 3. The parallel component moves the centre of the circle linearly at v cos θ. 4. Pitch = distance moved along the axis in one period = v cos θ · T = 2πm v cos θ/(eB). _Source: syllabus Physics Ch 4 "Moving Charges and Magnetism", §4.3_

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