JEECUP (UP Polytechnic) Section Formula — practice questions
5 free MCQs with worked solutions. Tap any question for the answer + explanation, or practice them all in the app.
Practice JEECUP (UP Polytechnic) Section Formula in the app →The position vector of the **midpoint** of the segment joining points with position vectors $\vec a$ and $\vecPoint $R$ divides the line segment joining $A(\vec a)$ and $B(\vec b)$ **internally** in the ratio $m : n$. ThThe point dividing the line segment joining $A(2, -6, 8)$ and $B(-1, 3, -4)$ internally in ratio $1:3$ has cooIf $\vec a, \vec b, \vec c$ are the position vectors of $A, B, C$ and $5\vec a - 3\vec b - 2\vec c = \vec 0$, Points $A(3, 2, p), B(q, 8, -10), C(-2, -3, 1)$ are collinear. The values of $p$ and $q$ are: