JEE Advanced Unit 2A: Newton's Laws and Translational Equilibrium — practice questions — page 4

Explore 92 free Unit 2A: Newton's Laws and Translational Equilibrium questions in JEE Advanced Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Unit 2A: Newton's Laws and Translational Equilibrium questions and exercises with answers

Showing questions 91–92 of 92.

A car travels 100 km at 50 km/h, then 100 km at 100 km/h. Average speed:Read the answer and worked solution →At what temperature does kT equal 1 eV?Read the answer and worked solution →

Worked practice questions

A car travels 100 km at 50 km/h, then 100 km at 100 km/h. Average speed:

75 km/h
66.67 km/h (harmonic mean for equal distances)
60 km/h
87.5 km/h

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Correct answer: B. 66.67 km/h (harmonic mean for equal distances)

**Time:** 100/50 + 100/100 = 2 + 1 = 3 h. Distance 200 km. v_avg = 200/3 ≈ 66.67 km/h. (Harmonic mean for equal distances.)

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At what temperature does kT equal 1 eV?

1000 K
100 K
300 K
11600 K (= 1.6e-19 / 1.38e-23 ≈ 11600)

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Correct answer: D. 11600 K (= 1.6e-19 / 1.38e-23 ≈ 11600)

kT = 1 eV → T = 1.6 × 10⁻¹⁹ / 1.38 × 10⁻²³ ≈ 11600 K. At room T (300 K), kT ≈ 1/40 eV = 0.025 eV.

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