The distance between two points P(x₁, y₁, z₁) and Q(x₂, y₂, z₂) in 3-D is
- √((x₂−x₁)² + (y₂−y₁)² + (z₂−z₁)²)
- |x₂−x₁| + |y₂−y₁| + |z₂−z₁|
- (x₂−x₁)·(y₂−y₁)·(z₂−z₁)
- √(x₂² + y₂² + z₂²)
Show answer and solution
Correct answer: A. √((x₂−x₁)² + (y₂−y₁)² + (z₂−z₁)²)
Extends the 2-D Pythagorean form to three coordinates.
The third term inside the square root accounts for the z separation.