alleryStart learning →The 10th term of the AP 3, 7, 11, ... is:
- 40
- 43
- 35
- 39
Show answer and solution
Correct answer: D. 39
1. First term a = 3, common difference d = 4.
2. nth term = a + (n − 1)d = 3 + 9·4 = 3 + 36 = 39.
_Source: TSICET 2024 PYQ Q.101 (Shift 1, AP)_
IPMAT Rohtak Sequences and Series — practice questions
Explore 4 free Sequences and Series questions in IPMAT Rohtak Mathematicalability. Open each question or exercise to read its content, reference answers and available explanation.
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The 10th term of the AP 3, 7, 11, ... is:Read the answer and worked solution →Sum of first 20 natural numbers:Read the answer and worked solution →GP with first term 2, common ratio 3. Find 5th term.Read the answer and worked solution →Sum of GP: 1 + 1/2 + 1/4 + ... to infinity =Read the answer and worked solution →
Worked practice questions
Sum of first 20 natural numbers:
- 420
- 200
- 220
- 210
Show answer and solution
Correct answer: D. 210
1. Sum 1 to n = n(n+1)/2.
2. n = 20: 20·21/2 = 210.
_Source: TSICET 2024 PYQ Q.102 (Shift 1, AP)_
GP with first term 2, common ratio 3. Find 5th term.
- 243
- 54
- 486
- 162
Show answer and solution
Correct answer: D. 162
1. nth term = a · r^(n−1) = 2 · 3⁴.
2. = 2 · 81 = 162.
_Source: TSICET 2024 PYQ Q.103 (Shift 1, GP)_
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