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Indian Navy SSR Motion in a Plane — practice questions

Explore 4 free Motion in a Plane questions in Indian Navy SSR Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Motion in a Plane questions and exercises with answers

Showing questions 1–4 of 4.

As per your syllabus, eqn 3.14, the magnitude of a vector A = A_x î + A_y ĵ is which expression?Read the answer and worked solution →As per your syllabus, components of vector A along x and y axes are scalars whose SIGN depends on which feature?Read the answer and worked solution →As per your syllabus, a ball thrown at 28 m/s at 30° above horizontal has maximum height of approximately which value? (g = 9.8 m/s²)Read the answer and worked solution →As per your syllabus, eqn 3.46, the centripetal acceleration expressed via angular speed ω is which?Read the answer and worked solution →

Worked practice questions

As per your syllabus, eqn 3.14, the magnitude of a vector A = A_x î + A_y ĵ is which expression?

  1. A_x · A_y
  2. √(A_x² + A_y²)
  3. A_x + A_y
  4. (A_x + A_y)²
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Correct answer: B. √(A_x² + A_y²)

syllabus eqn 3.14: A = √(A_x² + A_y²). Pythagoras on the perpendicular components.

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As per your syllabus, components of vector A along x and y axes are scalars whose SIGN depends on which feature?

  1. The angle θ with x-axis
  2. The magnitude only
  3. No factor
  4. Only the unit chosen
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Correct answer: A. The angle θ with x-axis

syllabus last paragraph: A_x = A cos θ can be +ve, -ve or zero depending on θ. Sign carries direction info.

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As per your syllabus, a ball thrown at 28 m/s at 30° above horizontal has maximum height of approximately which value? (g = 9.8 m/s²)

  1. 10.0 m
  2. 14.0 m
  3. 20.0 m
  4. 5.0 m
Show answer and solution

Correct answer: A. 10.0 m

syllabus Ex 3.8(a): h_m = (28 sin 30°)² / (2·9.8) = 14² / 19.6 = 10.0 m.

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