alleryStart learning →tan(45°) equals:
- ∞
- 0
- 1
- √3
Show answer and solution
Correct answer: C. 1
We have tan(45°) = sin(45°)/cos(45°).
That is tan(45°) = (1/√2)/(1/√2).
So tan(45°) = 1.
Indian Navy SSR (Sailor) Trigonometric Functions — practice questions
Explore 3 free Trigonometric Functions questions in Indian Navy SSR (Sailor) Mathematics. Open each question or exercise to read its content, reference answers and available explanation.
Practise Trigonometric Functions with Quill →Trigonometric Functions questions and exercises with answers
Showing questions 1–3 of 3.
Worked practice questions
The angle 90° in radians is:
- $\pi$ (full half-circle)
- $2\pi$ (full circle)
- $\pi/2$ (quarter circle)
- $\pi/4$ (one eighth)
Show answer and solution
Correct answer: C. $\pi/2$ (quarter circle)
180° = π radians.
So 90° = π/2 radians.
Quarter of a full circle (2π).
The function f(x) = tan x has vertical asymptotes at:
- $x = n\pi$ (multiples of π)
- $x = 2n\pi$ (multiples of 2π)
- $x = n\pi/2$ (all multiples of π/2)
- $x = (2n+1)\pi/2$ (odd multiples of π/2)
Show answer and solution
Correct answer: D. $x = (2n+1)\pi/2$ (odd multiples of π/2)
tan x = sin x / cos x.
Undefined where cos x = 0, which is at x = (2n+1)π/2 = π/2, 3π/2, 5π/2, ...
Period of tan x is π (NOT 2π).
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