alleryStart learning →tan(45°) equals:
- ∞
- 0
- 1
- √3
Show answer and solution
Correct answer: C. 1
We have tan(45°) = sin(45°)/cos(45°).
That is tan(45°) = (1/√2)/(1/√2).
So tan(45°) = 1.
Indian Navy SSR (Sailor) Sets, Relations and Functions — practice questions
Explore 48 free Sets, Relations and Functions questions in Indian Navy SSR (Sailor) Mathematics. Open each question or exercise to read its content, reference answers and available explanation.
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Showing questions 1–30 of 48.
tan(45°) equals:Read the answer and worked solution →For 3 sets A, B, C: n(A ∪ B ∪ C) =Read the answer and worked solution →Sort each inverse function into its domainRead the answer and worked solution →Tap every function whose domain is [−1, 1]Read the answer and worked solution →Match each inverse function to its domainRead the answer and worked solution →Match each inverse function to its principal value branchRead the answer and worked solution →Flip and pair: function with its principal rangeRead the answer and worked solution →Which principal ranges sit around zero, and which run 0 to π?Read the answer and worked solution →Tap every function whose principal range has a point removedRead the answer and worked solution →Name the principal value branchRead the answer and worked solution →Domain checkRead the answer and worked solution →Put the reasoning in order: why an inverse needs a restricted domainRead the answer and worked solution →True or false: existence of inversesRead the answer and worked solution →True or false: reading the tableRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Complete the summary tableRead the answer and worked solution →Complete the rule about restricting a domainRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Principal values worked in the chapterRead the answer and worked solution →Order the steps for finding a principal valueRead the answer and worked solution →True or false: principal valuesRead the answer and worked solution →Match each identity to the condition it needsRead the answer and worked solution →Assertion and reason: identitiesRead the answer and worked solution →Match each mathematician to the year your syllabus givesRead the answer and worked solution →Trace how trigonometry travelledRead the answer and worked solution →True or false: the historical noteRead the answer and worked solution →Complete the arc length relationRead the answer and worked solution →Match each identity to its nameRead the answer and worked solution →
Worked practice questions
For 3 sets A, B, C: n(A ∪ B ∪ C) =
- Random
- Σn(individual) - Σn(pairs) + n(A ∩ B ∩ C)
- n(A) + n(B) + n(C)
- n(A) × n(B) × n(C)
Show answer and solution
Correct answer: B. Σn(individual) - Σn(pairs) + n(A ∩ B ∩ C)
**Inclusion-exclusion for 3 sets:** n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(A∩C) - n(B∩C) + n(A∩B∩C).
Generalizes to n sets with alternating signs.
Sort each inverse function into its domain
Read exercise and reference answers
- Items
- Item
- sin⁻¹ x
- Category
- [−1, 1]
- Item
- cos⁻¹ x
- Category
- [−1, 1]
- Item
- cosec⁻¹ x
- Category
- R − (−1, 1)
- Item
- sec⁻¹ x
- Category
- R − (−1, 1)
- Item
- tan⁻¹ x
- Category
- R
- Item
- cot⁻¹ x
- Category
- R
- Categories
- Item
- [−1, 1]
- Item
- R − (−1, 1)
- Item
- R
Only sin⁻¹ and cos⁻¹ accept every value from −1 to 1. cosec⁻¹ and sec⁻¹ need |x| ≥ 1, so the open middle is cut out.
tan⁻¹ and cot⁻¹ accept any real number.
Source: syllabus Maths Part I, Ch 2 Inverse Trigonometric Functions.
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