The value of $\displaystyle\lim_{x\to 3}\frac{x^2-9}{x-3}$ is:
- 3
- 6
- 9
- 0
Show answer and solution
Correct answer: B. 6
(x²−9)/(x−3) = x+3 for x≠3, so the limit is 3+3 = 6.
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Correct answer: B. 6