alleryStart learning →tan(45°) equals:
- ∞
- 0
- 1
- √3
Show answer and solution
Correct answer: C. 1
We have tan(45°) = sin(45°)/cos(45°).
That is tan(45°) = (1/√2)/(1/√2).
So tan(45°) = 1.
Indian Navy SSR (Sailor) Class12 Functions Basics — practice questions
Explore 49 free Class12 Functions Basics questions in Indian Navy SSR (Sailor) Mathematics. Open each question or exercise to read its content, reference answers and available explanation.
Practise Class12 Functions Basics with Quill →Class12 Functions Basics questions and exercises with answers
Showing questions 1–30 of 49.
tan(45°) equals:Read the answer and worked solution →The angle 90° in radians is:Read the answer and worked solution →The function f(x) = tan x has vertical asymptotes at:Read the answer and worked solution →Sort each inverse function into its domainRead the answer and worked solution →Tap every function whose domain is [−1, 1]Read the answer and worked solution →Match each inverse function to its domainRead the answer and worked solution →Match each inverse function to its principal value branchRead the answer and worked solution →Flip and pair: function with its principal rangeRead the answer and worked solution →Which principal ranges sit around zero, and which run 0 to π?Read the answer and worked solution →Tap every function whose principal range has a point removedRead the answer and worked solution →Name the principal value branchRead the answer and worked solution →Domain checkRead the answer and worked solution →Put the reasoning in order: why an inverse needs a restricted domainRead the answer and worked solution →True or false: existence of inversesRead the answer and worked solution →True or false: reading the tableRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Complete the summary tableRead the answer and worked solution →Complete the rule about restricting a domainRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Principal values worked in the chapterRead the answer and worked solution →Order the steps for finding a principal valueRead the answer and worked solution →True or false: principal valuesRead the answer and worked solution →Match each identity to the condition it needsRead the answer and worked solution →Assertion and reason: identitiesRead the answer and worked solution →Match each mathematician to the year your syllabus givesRead the answer and worked solution →Trace how trigonometry travelledRead the answer and worked solution →True or false: the historical noteRead the answer and worked solution →Complete the arc length relationRead the answer and worked solution →
Worked practice questions
The angle 90° in radians is:
- $\pi$ (full half-circle)
- $2\pi$ (full circle)
- $\pi/2$ (quarter circle)
- $\pi/4$ (one eighth)
Show answer and solution
Correct answer: C. $\pi/2$ (quarter circle)
180° = π radians.
So 90° = π/2 radians.
Quarter of a full circle (2π).
The function f(x) = tan x has vertical asymptotes at:
- $x = n\pi$ (multiples of π)
- $x = 2n\pi$ (multiples of 2π)
- $x = n\pi/2$ (all multiples of π/2)
- $x = (2n+1)\pi/2$ (odd multiples of π/2)
Show answer and solution
Correct answer: D. $x = (2n+1)\pi/2$ (odd multiples of π/2)
tan x = sin x / cos x.
Undefined where cos x = 0, which is at x = (2n+1)π/2 = π/2, 3π/2, 5π/2, ...
Period of tan x is π (NOT 2π).
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