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Indian Navy SSR (Sailor) Areas Related to Circles — practice questions

Explore 3 free Areas Related to Circles questions in Indian Navy SSR (Sailor) Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Areas Related to Circles questions and exercises with answers

Showing questions 1–3 of 3.

The formula for the area of a sector of a circle of radius r and angle theta (in degrees) isRead the answer and worked solution →A wire is bent in the form of a circle of radius 28 cm. The same wire is then re-bent in the form of a square. The side of the square isRead the answer and worked solution →A circular flower bed has area 49 pi sq m. Its diameter isRead the answer and worked solution →

Worked practice questions

The formula for the area of a sector of a circle of radius r and angle theta (in degrees) is

  1. (theta/360) × pi × r squared
  2. (theta/180) × pi × r
  3. pi × r × theta
  4. (theta/360) × 2 × pi × r
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Correct answer: A. (theta/360) × pi × r squared

1. A full circle (360 degrees) has area pi × r squared. 2. A sector of angle theta is the fraction theta/360 of that. 3. Hence area = (theta/360) × pi × r squared. _Source: syllabus Mathematics, Ch 11 "Areas Related to Circles", §11.2_

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A wire is bent in the form of a circle of radius 28 cm. The same wire is then re-bent in the form of a square. The side of the square is

  1. 22 cm
  2. 44 cm
  3. 88 cm
  4. 14 cm
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Correct answer: B. 44 cm

1. Wire length = circumference = 2 × (22/7) × 28 = 176 cm. 2. Perimeter of square = 4 × side = 176; side = 44 cm. 3. Hence 44 cm. _Source: syllabus Mathematics, Ch 11 "Areas Related to Circles", §11.2_

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A circular flower bed has area 49 pi sq m. Its diameter is

  1. 21 m
  2. 7 m
  3. 14 m
  4. 28 m
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Correct answer: C. 14 m

1. Area = pi × r squared = 49 pi, so r squared = 49 and r = 7 m. 2. Diameter = 2 × r. 3. = 14 m. _Source: syllabus Mathematics, Ch 11 "Areas Related to Circles", §11.2_

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