When the separation between the plates of an air parallel-plate capacitor is doubled (keeping plate area constant), the capacitance
- remains unchanged
- becomes one-fourth
- doubles
- halves
Show answer and solution
Correct answer: D. halves
1. C = ε₀ A / d.
2. Doubling d gives C' = ε₀ A / (2d) = C/2.
3. So capacitance halves; the field also halves at fixed Q.
_Source: syllabus Physics Part I, Ch 2 §2.12_