By substitution u = x², ∫ 2x sin(x²) dx equals:
- -cos(x²) + C
- -sin(x²) + C
- cos(x²) + C
- sin(x²) + C
Show answer and solution
Correct answer: A. -cos(x²) + C
Let u = x², du = 2x dx.
Integral becomes ∫ sin u du = -cos u + C = -cos(x²) + C.
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Correct answer: A. -cos(x²) + C
Correct answer: C. ln |x/(x+1)| + C
Correct answer: B. 1/2